If 1.2 kW of power is dissipated by a resistor when supplied with 110 V, what is the amperage?

To determine the amperage flowing through the resistor when 1.2 kW of power is dissipated at a voltage of 110 V, we can use the formula relating power (P), voltage (V), and current (I):

[ P = V \times I ]

We can rearrange this formula to solve for current (I):

[ I = \frac{P}{V} ]

Substituting in the given values:

• Power (P) = 1.2 kW = 1200 W (since 1 kW = 1000 W)

• Voltage (V) = 110 V

Now, plugging these values into the formula gives:

[ I = \frac{1200 , W}{110 , V} ]

Calculating this results in:

[ I = 10.909 , A ]

Rounding this to two decimal places gives approximately 10.91 A, confirming that the calculated amperage is correct.

This answer is derived from the fundamental relationship between power, voltage, and current in electrical circuits, demonstrating a clear application of Ohm's law.