What quantity of heat is needed to raise the temperature of 6.3 kg of glass from 6°C to 210°C with a specific heat of 670 J/kg K?

Prepare for the ABSA 4th Class Exam with our comprehensive quiz. Explore flashcards and multiple choice questions, complete with hints and explanations. Ace your exam with confidence!

To determine the quantity of heat required to raise the temperature of a substance, the formula used is:

[ Q = m \cdot c \cdot \Delta T ]

where ( Q ) is the heat energy (in joules), ( m ) is the mass of the substance (in kilograms), ( c ) is the specific heat capacity (in joules per kilogram per Kelvin), and ( \Delta T ) is the change in temperature (in degrees Celsius or Kelvin).

In this case, the mass of the glass is given as 6.3 kg, the specific heat is 670 J/kg K, and the change in temperature can be calculated as follows:

[ \Delta T = T_{\text{final}} - T_{\text{initial}} = 210°C - 6°C = 204°C ]

Now, substitute the values into the formula:

[ Q = 6.3 , \text{kg} \cdot 670 , \text{J/kg K} \cdot 204 , \text{K} ]

First, calculate ( 6.3 \times 670 = 4221 , \text{J/K} ).

Next

Subscribe

Get the latest from Examzify

You can unsubscribe at any time. Read our privacy policy